(-t^2)-17t=0

Solution for (-t^2)-17t=0 equation:

(-t^2)-17t=0

We get rid of parentheses

-t^2-17t=0

We add all the numbers together, and all the variables

-1t^2-17t=0

a = -1; b = -17; c = 0;
Δ = b2-4ac
Δ = -172-4·(-1)·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-17}{2*-1}=\frac{0}{-2}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+17}{2*-1}=\frac{34}{-2}
=-17
$